- a km/hr = [a * 5/18]m/s.
- a m/s = [a * 18/5] km/hr.
- Time taken by a train of length l metres to pass a pole or a

standing man or a signal post is equal to the time taken by the train

to cover l metres. - Time taken by a train of length l metres to pass a stationary

object of length b metres is the time taken by the train to cover (l +

b) metres. - Suppose two trains or two bodies are moving in the same

direction at u m/s and v m/s, where u>v, then their relatives speed

= (u – v) m/s. - Suppose two trains or two bodies are moving in opposite

directions at u m/s and v m/s, then their relative speed is = (u + v)

m/s - If two trains of length a metres and b metres are moving in

opposite directions at u - If two trains of length a metres and b metres are moving in the same direction at u m/s and v m/s, then the time taken by the faster train to cross the slower train = (a + b)/(u – v) sec.
- a km/hr = [a * 5/18]m/s.

a m/s = [a * 18/5] km/hr.

Time taken by a train of length l metres to pass a pole or a

standing man or a signal post is equal to the time taken by the train to cover l metres. - Time taken by a train of length l metres to pass a stationary

object of length b metres is the time taken by the train to cover (l + b) metres. - Suppose two trains or two bodies are moving in the same

direction at u m/s and v m/s, where u>v, then their relatives speed

= (u – v) m/s. - Suppose two trains or two bodies are moving in opposite

directions at u m/s and v m/s, then their relative speed is = (u + v) m/s - If two trains of length a metres and b metres are moving in

opposite directions at u If two trains of length a metres and b metres are moving in the same direction at u m/s and v m/s, then the time taken by the faster

train to cross the slower train = (a + b)/(u – v) sec. - If two trains (or bodies) start at the same time from points A and B towards each other and after crossing they take a and b sec in

reaching B and A respectively, then

(A’s speed):(B’s speed) = (√b : √a)

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