PROBLEMS ON TRAINS ->IMPORTANT FORMULA

  1. a km/hr = [a * 5/18]m/s.
  2. a m/s = [a * 18/5] km/hr.
  3. Time taken by a train of length l metres to pass a pole or a
    standing man or a signal post is equal to the time taken by the train
    to cover l metres.
  4. Time taken by a train of length l metres to pass a stationary
    object of length b metres is the time taken by the train to cover (l +
    b) metres.
  5. Suppose two trains or two bodies are moving in the same
    direction at u m/s and v m/s, where u>v, then their relatives speed
    = (u – v) m/s.
  6. Suppose two trains or two bodies are moving in opposite
    directions at u m/s and v m/s, then their relative speed is = (u + v)
    m/s
  7. If two trains of length a metres and b metres are moving in
    opposite directions at u
  8. If two trains of length a metres and b metres are moving in the same direction at u m/s and v m/s, then the time taken by the faster train to cross the slower train = (a + b)/(u – v) sec.
  9. a km/hr = [a * 5/18]m/s.
    a m/s = [a * 18/5] km/hr.
    Time taken by a train of length l metres to pass a pole or a
    standing man or a signal post is equal to the time taken by the train to cover l metres.
  10. Time taken by a train of length l metres to pass a stationary
    object of length b metres is the time taken by the train to cover (l + b) metres.
  11. Suppose two trains or two bodies are moving in the same
    direction at u m/s and v m/s, where u>v, then their relatives speed
    = (u – v) m/s.
  12. Suppose two trains or two bodies are moving in opposite
    directions at u m/s and v m/s, then their relative speed is = (u + v) m/s
  13. If two trains of length a metres and b metres are moving in
    opposite directions at u If two trains of length a metres and b metres are moving in the same direction at u m/s and v m/s, then the time taken by the faster
    train to cross the slower train = (a + b)/(u – v) sec.
  14. If two trains (or bodies) start at the same time from points A and B towards each other and after crossing they take a and b sec in
    reaching B and A respectively, then
    (A’s speed):(B’s speed) = (√b : √a)
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